CODEWITHSUNDEEP
pythonjsonurllib2
Iain Shelvington
Iain Shelvington

Reputation: 32244

HTTP Error 400 when trying to send json data with urllib2 to toggl api

When using the following code to connect to the toggl api I connect and am authorised just fine.

username = token
password = 'api_token'
url = 'http://www.toggl.com/api/v3/tasks.json'

req = urllib2.Request(url)
auth_string = base64.encodestring('%s:%s' % (username, password))
req.add_header("Authorization", "Basic %s" % auth_string)
f = urllib2.urlopen(req)
response = f.read()

When I try to start a new task I have to send data in json format. To test, I created my json object and added the data to my Request object

data = simplejson.dumps({
    'task':{
        'duration': 1,
        'billable': True,
        'start': '2010-02-12T16:19:45+02:00',
        'description': 'This is a test task',
    }
})
req = urllib2.Request(url, data)

But now the only response I recieve is "urllib2.HTTPError: HTTP Error 400: Bad Request". Can someone please point me to where I am going wrong?

Upvotes: 2

Views: 3899

Answers (2)

Iain Shelvington
Iain Shelvington

Reputation: 32244

I have figured it out. Thanks to TryPyPy, I needed to add a 'Content-type' header to my request.

I had to strip any newline and linefeed characters from my authentication string.

auth_string = base64.encodestring('%s:%s' % (username, password)).strip()

Upvotes: 2

TryPyPy
TryPyPy

Reputation: 6434

According to the API documentation, you're missing at least a header. Try:

req = urllib2.Request(url, data, {"Content-type": "application/json"})

If that's not enough, try using urllib.urlencode on data. If that's still not enough, add a user:password to the request, like in the API example.

Upvotes: 3

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