CODEWITHSUNDEEP
c++binarybit-manipulation
MPardo3
MPardo3

Reputation: 57

Confusion with Bitwise NOT on char c++

I'm currently reading "C++ Primer" and I'm on a section about bitwise operators.

I get it but I dont get this exercise..

What is the value of ~'q' << 6 on a machine with 32-bit ints and 8 bit chars, that uses Latin-1 character set in which 'q' has the bit pattern 01110001?

The Answer given was:

The final value in decimal is -7296.

How did they get there?

Basically, I need an explanation of what the whole ~'q' << 6 means and how they got that negative number.

Upvotes: 0

Views: 577

Answers (1)

Dark Sorrow
Dark Sorrow

Reputation: 1897

When 'q' = 0b01110001 then in decimal format q=113. Not q(~q) = ~113 = -114 (0b1111111110001110). When we left shift -114 by 6 we get -7296 (0b1110001110000000).

Upvotes: 2

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