CODEWITHSUNDEEP
phpreflectionnamespaces
phadaphunk
phadaphunk

Reputation: 13313

Why can't I instantiate a new object from a string without a full namespace

Why is it that when I want to instantiate a new object from a string like so 

use Foo\Bar\Test

$name = "Test";
$test = new $name();

I get an exception since Test is not found in the global namespace. I know I could simply use the full namespace when instantiating : 

$name = "Foo\\Bar\\Test";
$test = new $name();

But it kind of doesn't fit the use I planned to make out of it. I know it's probably a design flaw on my part for the "doesn't fit" but it still raised the question as to why this cannot be done. Also, if it exists, are there alternatives to this approach? (beside __NAMESPACE__ as in this example I am not currently in Foo\Bar).

Upvotes: 3

Views: 123

Answers (1)

Philipp
Philipp

Reputation: 15629

You have to differentiate between the information, the compiler resolves at compile and at runtime. At compiletime he resolves alias resolution.

use Foo\Bar\Test

So every occurance of Test would be resolved to \Foo\Bar\Test.

Creating new objects instead is an runtime operation. At this point, there isn't any alias or namespace resolution. The only thing the runtime (new operator) knows at this time, is the given name. If you pass a class, it must always be the full qualified name.

Upvotes: 3

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