CODEWITHSUNDEEP
regexscala
Greg
Greg

Reputation: 11512

How can I exclude newlines in Scala RegexParsers matches?

I'd like to have something that matches basically anything to end-of-line of a multi-line string. Ideally something like this:

def almostAnything: Parser[String] = """[^\r\n]+""".r ^^ { _.toString.trim }

Problem is... this doesn't work. It ignores the negated \n and just keeps matching away onto the next chunk of string after the \n.

Why is that, and how can I successfully match anything up to end-of-line (!= end-of-string)?

Upvotes: 0

Views: 181

Answers (1)

Nicolas Rinaudo
Nicolas Rinaudo

Reputation: 6168

I'm not sure how the parsers work, but the problem you're encountering here is not with your regular expression, but with the way Regex works.

By defaults, Regexs are anchored - they expect to match the entire string. If you want partial matches (and it seems that you do), you must unanchor them.

For example:

 val sameLine = """([^\r\n]+)""".r.unanchored

 "45ft\n  something" match {
   case sameLine(c) => Some(c)
   case _ => None
 }

This yields Some(45ft).

Upvotes: 1

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