Reputation: 13
In the following code I am retrieving data from a MariaDB database, then it should be listing each relevant entry from the database with echo "Username: " . $row['username'];
It does not seem to be printing, is there something I'm doing wrong.
(I know it's insecure)
<?php
$connection = @mysqli_connect("localhost","root","","jet")
OR die('Could not connect' .
mysqli_connect_error());
if($connection->connect_error){
$sql="SELECT username FROM userinfo WHERE username LIKE '%" . $_POST['search'] . "%';";
$res=$con->query($sql);
while($row=$res->fetch_assoc()){
echo "Username: " . $row['username'];
}
}
mysqli_close($connection);
?>
<form action="search.php" method="post">
<input type="text" name="search" id="bug">
<input type="submit" name="submit" value="search" id="rat">
</form>
I'm new to stack overflow and my English isn't great, if this is posted in the wrong place please warn me and I will delete. Thank you
Upvotes: 1
Views: 93
Reputation: 2327
Error is in this line
$res=$con->query($sql);
Because your connection variable is $connection
. Check This
Change this to
$res=$connection->query($sql);
it may work.
Code like below
<?php
$connection = @mysqli_connect("localhost","root","","jet");
if($connection->connect_error){//show error if not connection failed
die("Connection failed: " . $connection->connect_error);
}
$sql="SELECT username FROM userinfo WHERE username LIKE '%" . $_POST['search'] . "%';";
$res=$connection->query($sql);
while($row=$res->fetch_assoc()){
echo "Username: " . $row['username'];
}
mysqli_close($connection);
?>
Upvotes: 1