CODEWITHSUNDEEP
phpnumber-formatting
masroore
masroore

Reputation: 10135

Format number from Zero to Six decimal points in PHP

I want to display numbers up to 6 decimal points.

Like this:

99.0000001 -> 99
99.000001  -> 99.000001
99.00001   -> 99.00001
99.0001    -> 99.0001
99.001     -> 99.001
99.01      -> 99.01
99.10      -> 99.10
99.00      -> 99

What would be an elegant way to do this in PHP?

Upvotes: -2

Views: 1562

Answers (3)

Saad
Saad

Reputation: 1

// Array of values to divide
$numerators = [1, 1, 1];
$denominators = [2, 3, 6];

// Loop through and calculate the result
foreach ($numerators as $key => $numerator) {
    $denominator = $denominators[$key];
    $result = $numerator / $denominator;
    // Print the result with 6 decimal places
    printf("%0.6f\n", $result);
}

Expected Output:

0.500000
0.333333
0.166667

You can use "%0.6f\n to achieve this

Upvotes: 0

Lawrence Cherone
Lawrence Cherone

Reputation: 46620

Use round(), with precision 6

<?php
echo round(99.0000001, 6).PHP_EOL;
echo round(99.000001, 6).PHP_EOL;
echo round(99.00001, 6).PHP_EOL;
echo round(99.0001, 6).PHP_EOL;
echo round(99.001, 6).PHP_EOL;
echo round(99.01, 6).PHP_EOL;
echo round(99.10, 6).PHP_EOL;
echo round(99.00, 6).PHP_EOL;

https://3v4l.org/5lWCa

Result:

99
99.000001
99.00001
99.0001
99.001
99.01
99.1
99

Upvotes: 2

Christo Muller
Christo Muller

Reputation: 36

You can use this. Removal of addition digits after 6th decimal digit.

$z = 99.0000011;  
$y = floor($z * 1000000) / 1000000;

Then to calculate amount of digits after decimal remaining.

$str = "$y";
$dcount = strlen(substr(strrchr($str, "."), 1));

Now we have to determine if the value should have decimals or not and if so , need to have 2 or more decimals.

$a = 0; 
If ($dcount == 1) {$a = $dcount+1;} 
else {$a = $dcount;} 
$x = number_format((float)$y, $a, '.', '');

$x would be the required result you are looking for.

Upvotes: 1

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