Reputation: 958
I have a need, in a site I'm building, for a list component that is reused several times. However, the list is purely for rendering and is not responsible for the state of the app at all. I know you either cannot, or are not supposed to have dumb components containing any logic, but I am not sure how to proceed without using a smart component, which is entirely unnecessary. Here is my smart component that works:
class Menu extends Component {
renderItems(items) {
return this.props.items.map((i, index) => {
return (
<li key={index} style={{marginLeft: 10}}>
{i}
</li>
)
});
}
render() {
const { listStyle } = styles;
return (
<div>
<ul style={listStyle}>
{this.renderItems()}
</ul>
</div>
)
}
}
And I've tried this:
function Menu(props) {
return props.items.map((i, index) => {
<li key={index} style={{marginLeft: 10}}>
{i}
</li>
});
}
And then calling it inside Nav like this, which does not throw an error but does not render anything from menu either:
const Nav = () => {
const { listStyle, containerStyle } = styles;
return (
<div style={containerStyle}>
<Logo url={'#'}
src={PickAPlayLogo}
width={300} />
<Menu items={pageLinks} />
<Menu items={socialMediaLinks} />
<Logo url={'#'}
src={AppStoreLogo}
width={170} />
</div>
);
};
Also, worth noting, I have never come across a function that is supposed to be rendered like a component, but was trying it based on the example on this page
Upvotes: 1
Views: 1615
Reputation: 81
Heres an answer similar to what you have going on
function Menu(props) {
this.renderItems = () => {
return (
<ul>
{props.items.map((i, index) => {
return (
<li>{i}</li>
)
})}
</ul
)
}
return(
this.renderItems()
)
}
Upvotes: 1
Reputation: 958
Here we go:
function Menu(props) {
const {listStyle} = styles;
const listItems = props.items.map((i, index) =>
<li key={index} style={{marginLeft: 10}}>
{i}
</li>
);
return (
<ul style={listStyle}>{listItems}</ul>
);
}
Upvotes: 0