Reputation: 13
(You'd think this would be easy, but I'm stumped.)
I'm converting an iOS note to a text file, and the note contains "0." and "?" whenever there is a list or bullet.
This was a bulleted list
? item 20
? Item 21
? Item 22
I'm having so much problem replacing the "?"
I don't want to replace a legitimate question mark at the end of a sentence, but I want to replace the "?" bullets with "-" (preferably anywhere in the line, not just at the beginning)
I tried these searches - no luck
set line "? item 20"
set index_bullet [string first "(\s|\r|\n)(\?)" $line]
set index_bullet [string first "(!\w)(\?)" $line]
set index_bullet [string first ^\? $line]
This works, but it would match any question mark
set index_bullet [string first \? $line]
Does anyone know what I'm doing wrong? How do I find and replace only question mark bullets with a "-"?
Thank you very much in advance
Upvotes: 1
Views: 3152
Reputation: 137587
If you're really wanting to replace a question mark where you've got a regular expression that describes the rule, the regsub
command is the right way. (The string first
command finds literal substrings only. The string match
command uses globbing rules.) In this case, we'll use the -all
option so that every instance is replaced:
set line "? item 20"
set replaced [regsub -all {(\s|^)\?(\s)} $line {\1-\2}]
puts "'$line' --> '$replaced'"
# Prints: '? item 20' --> '- item 20'
The main tricks to using regular expressions in Tcl are, as much as possible, to keep REs and their replacements in braces so that the you can use Tcl metacharacters (e.g., backslash or square brackets) without having to fiddle around a lot.
Also, \s
by default will match a newline.
Upvotes: 1
Reputation: 13252
It seems likely that a character used to indicate a list item is the first character on the line or the first character after optional whitespace. To match a question mark at the beginning of a line:
string match {\?*} $line
or
string match \\?* $line
The braces or doubled backslash keeps the question mark from being treated as a string match
metacharacter.
To find a question mark after optional whitespace:
string match {\?*} [string trimleft $line]
The command returns 1 if it finds a match, and 0 if it doesn't.
To do this with string first
, use
if {[string first ? [string trimleft $line]] eq 0} ...
but in that case, keep in mind that the index returned from string first
isn't the true location of the question mark. (Use
==
instead of eq
if you have an older Tcl).
When you have determined that the line contains a question mark in the first non-whitespace position, a simple
set line [regsub {\?} $line -]
will perform a single substitution regardless of where it is.
Documentation: regsub, string, Syntax of Tcl regular expressions
Upvotes: 1
Reputation: 13
I figured it out. I did it in two steps:
1) First find the "?"
set index_bullet [string first "\?" $line]
2) Then filter out "?" that is not a bullet
set index_question_mark [string first "\w\?" $line]
I have a solution, but please post if you have a better way of doing this. Thanks!
Upvotes: 0