Reputation: 21
How can I check a div by class (top
) if he has an other div with an other class(bottom
) inside so that the function returns a true or false in an array.
<div class="top">
<div class="bottom"></div>
</div>
<div class="top"></div>
I tried this but It only told me if the <div class="top">
contains the <div class="bottom">
and not if the <div class="top">
comes without the <div class="bottom">
if ($(".top").find(".bottom").length > 0){
}
Upvotes: 2
Views: 31
Reputation: 381
You can exclude the ".top"-div's without ".bottom" with the has
-method:
$('.top').has('.bottom').css('background', '#bada55');
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="top">
top has bottom
<div class="bottom">bottom</div>
</div>
<div class="top">top without bottom</div>
Upvotes: 1