Reputation: 141
Does someone knows how to get that result bellow ?
There is a sceneario
ID DATE Description
00041454707 27/07/17 Hospital Sugisawa Pronto Atendimento
00041454707 27/07/17 Hospital Pequeno Príncipe
00041454707 28/07/17 Hospital Sugisawa Pronto Atendimento
Result expected :
ID DATE Description
00041454707 27/07/17 Hospital Sugisawa Pronto Atendimento | Hospital Pequeno Príncipe
00041454707 28/07/17 Hospital Sugisawa Pronto Atendimento
Look at result ,I've grouped the first and second one , which has same date 27/07/17 , and concatened in Description field .
I dunno have much background in DB2 .
DB2 V11.1
Upvotes: 0
Views: 4822
Reputation: 86
SELECT id, dateval,
LISTAGG(descval, ' | ') AS descvals
FROM yourtable
GROUP BY id, dateval
As already mentioned by others here, the trick is done by LISTAGG function. GROUP BY operator collects the rows into a group, and LISTAGG collects the values into a string with the separator specified.
Upvotes: 2