How to get mouse clicks

Question

I'm programming a small game with Pygame and I'm not sure how to get mouse clicks. I've gotten a bit of it figured out, but honestly I'm not having the best of times.

Here's what I have:

import pygame

pygame.init()

def menu():
    title_font = pygame.font.SysFont("monospace",64)
    button_font = pygame.font.SysFont("monospace", 30)
    screen_size = (1280,950)
    screen = pygame.display.set_mode(screen_size)

    background = (255,255,255)
    screen.fill(background)
    play_button = pygame.Rect(250,600,200,100)
    quit_button = pygame.Rect(850,600,200,100)
    controls_button = pygame.Rect(550,600,200,100)
    pygame.draw.rect(screen, (0,255,0), play_button)
    pygame.draw.rect(screen, (255,0,0), quit_button)
    pygame.draw.rect(screen, (255,229,0), controls_button)
    title = title_font.render("Fightastic!", 1, (0,0,0))
    screen.blit(title, (450,300))
    play_text = button_font.render("START",1,(0,0,0))
    screen.blit(play_text, (310,635))
    quit_text = button_font.render("QUIT",1,(0,0,0))
    screen.blit(quit_text, (910,635))
    controls_text = button_font.render("CONTROLS",1,(0,0,0))
    screen.blit(controls_text, (580,635))
    buttons = [play_button, quit_button, controls_button]

    while True:

        events = pygame.event.get()
        for event in events:
            if event.type == pygame.QUIT:
                exit()

        mouse_cursor = pygame.mouse.get_pos()
        mouse_pressed = pygame.mouse.get_pressed()

        option = 0
        for i in range(len(buttons)):
            if buttons[i].collidepoint( mouse_cursor):
                option = i+1

        if option == 1:
            print ("YO I GOT CLICKED")
        elif option == 2:
            print ("CLICKED MY DUDE")
        elif option == 3:
            quit()

    pygame.display.update()

menu()

The game's menu is the only part that will require clicks so that's all I've shown.

Thanks!

furas · Accepted Answer

You already have pygame.mouse.get_pressed() so use it to check which button was clicked.

    option = 0

    if mouse_pressed[0]: # check if left button was clicked
        for i, but in enumerate(buttons, 1): # get button and its number
            if but.collidepoint(mouse_cursor): # check collision
                option = i # remember button number
                break      # no need to check other buttons

But using pygame.mouse.get_pressed() makes one problem - it returns True all the time you hold mouse button pressed (so it looks like many clicks in every second) so if you change button on screen and new button will be in the same place then it will automatically click in new button. Better use event.type == pygame.MOUSEBUTTONDOWN which create only one click.

while True:

    option = 0

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            exit()
        if event.type == pygame.MOUSEBUTTONDOWN:
            for i, but in enumerate(buttons, 1):
                if but.collidepoint(event.pos):
                    option = i
                    break # no need to check other buttons

    if option == 1:
        print ("YO I GOT CLICKED")
    elif option == 2:
        print ("CLICKED MY DUDE")
    elif option == 3:
        quit()

    pygame.display.update()

BTW:

You could keep buttons with callbacks (functions names without ())

    buttons = [
        (play_button, play_function),
        (controls_button, control_function),
        (quit_button, quit_function),
    ]

and then you would call function/callback directly (using ()) without option

            if event.type == pygame.MOUSEBUTTONDOWN:
                for rect, callback in buttons:
                    if rect.collidepoint(event.pos):
                        callback() # execute function
                        break # no need to check other buttons

Full working code

import pygame

# --- constants --- (UPPER_CASE_NAMES)

SCREEN_WIDTH = 1280
SCREEN_HEIGHT = 950

WHITE = (255, 255, 255)

# --- functions --- (lower_case_names)

def play_function():
    print("YO I GOT CLICKED")

def controls_function():
    print("CLICKED MY DUDE")

def quit_function():
    pygame.quit()
    quit()

def menu(screen):

    # - init -

    title_font = pygame.font.SysFont("monospace", 64)
    button_font = pygame.font.SysFont("monospace", 30)

    # - objects -

    play_button = pygame.Rect(250,600,200,100)
    quit_button = pygame.Rect(850,600,200,100)
    controls_button = pygame.Rect(550,600,200,100)

    buttons = [
        (play_button, play_function),
        (controls_button, controls_function),
        (quit_button, quit_function),
    ]

    # - draws -

    screen.fill(WHITE)

    title = title_font.render("Fightastic!", 1, (0,0,0))
    screen.blit(title, (450,300))


    pygame.draw.rect(screen, (0,255,0), play_button)
    play_text = button_font.render("START",1,(0,0,0))
    screen.blit(play_text, (310,635))

    pygame.draw.rect(screen, (255,0,0), quit_button)
    quit_text = button_font.render("QUIT",1,(0,0,0))
    screen.blit(quit_text, (910,635))

    pygame.draw.rect(screen, (255,229,0), controls_button)
    controls_text = button_font.render("CONTROLS",1,(0,0,0))
    screen.blit(controls_text, (580,635))

    pygame.display.update()

    # - mainloop -

    clock = pygame.time.Clock()

    while True:

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                exit()
            if event.type == pygame.MOUSEBUTTONDOWN:
                for rect, callback in buttons:
                    if rect.collidepoint(event.pos):
                        callback() # execute function
                        break # no need to check other buttons

        clock.tick(5) # 5 FPS - to slow down game and use less CPU

# --- main ---

pygame.init()
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))

menu(screen)

How to get mouse clicks

Answers (2)

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