CODEWITHSUNDEEP
phpswitch-statement
Tom Granot
Tom Granot

Reputation: 1850

switch function variable not showing

I've got this switch function that is suppose to get the value of a parameter passed in a query string, and upon it decide the value of the variable:

<?php

switch($_REQUEST['textcolor']){
case "white":
$textcolor = $white;
break;
case "black":
$textcolor = $black;
break;
}

?>

The $_REQUEST gets it's value from this link:

 <a href="index2.php?status=Busy&codigo2=<?php echo $codigo2; ?>&textcolor=white">

and this is the form in which I have a hidden element that;s suppose to show the value, but does not:

 <form>
            <input type="hidden" value="<?= $textcolor ?>">
        </form>

Any ideas why the $textcolor variable is not showing?

EDIT: Solved, the reason was indeed variable not declared. Thanks!

Upvotes: 0

Views: 209

Answers (2)

powtac
powtac

Reputation: 41050

Add a last case in the switch

default:
   die('textcolor is not '.$black.' or '.$white);
break;

Upvotes: 1

Mark Baker
Mark Baker

Reputation: 212412

switch($_REQUEST['textcolor']){
    case "white":
        $textcolor = $white;
        break;
    case "black":
        $textcolor = $black;
        break;
}

Where are $white and $black defined?

EDIT

Do:

$white = 'white';
$black = 'black';

switch($_REQUEST['textcolor']){
    case "white":
        $textcolor = $white;
        break;
    case "black":
        $textcolor = $black;
        break;
}

and see what happens

Upvotes: 1

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