Reputation: 297
Not an expert in SQL. I am using postgres database with EF migration. Stuck with this requirement. Here it goes.
My table is like this:
A B C D
20 1 1 1
59 0 0 1
57 1 1 1
10 1 0 0
30 1 1 1
15 0 0 0
The order of rows is like oldest to latest(top to bottom).
Half query I have from my project is as below:
SELECT dcr."A"
FROM "DCR" dcr
LEFT JOIN "DCM" dcm ON "Id" = dcm."DCRID"
LEFT JOIN "DC" dc ON dc."Id" = dcm."DCID"
WHERE dcr."B" != 0
AND dcr."C" != 0
AND dcr."B" != 0
ORDER BY "UtcDate" desc
limit(1)
This will fetch me the first part value of latest A when it matches condition. But not the Max part and the division part as explained below.
I want to find the result of ((latest A where B = C = D = 1 divided by max of A in its previous rows where B = C = D = 1) - 1) * 100.
I want this to happen in single query and there are multiple groups like this. Lets say the table contains around 60 rows and we can group them based on some other column. Each group should evaluate this above formula.
Expected result for above example should be:
result = ((30 / 57) - 1) * 100 = (0.5263 - 1) * 100 = -47.73
Upvotes: 1
Views: 97
Reputation: 11
maybe something like this?
select (t1."A"/max(t2."A"))*100 from
(select row_number() over() as id,*
from t
where t."A"=1 and t."B" =1 and t."C"=1 ) as t1
join
(select row_number() over() as id,*
from t
where t."A"=1 and t."B" =1 and t."C"=1 ) as t2
on t1.id>t2.id
group by t1."A",t1."E"
Upvotes: 0
Reputation: 25351
You can use a subquery to get the max. I don't know why you're writing the query in that strange style, but I will keep it:
SELECT dcr."A" / (SELECT MAX("A")
FROM "DCR"
WHERE dcr."B" != 0
AND dcr."C" != 0
AND dcr."D" != 0)) - 1) * 100
FROM "DCR" dcr
LEFT JOIN "DCM" dcm ON "Id" = dcm."DCRID"
LEFT JOIN "DC" dc ON dc."Id" = dcm."DCID"
WHERE dcr."B" != 0
AND dcr."C" != 0
AND dcr."D" != 0
ORDER BY "UtcDate" desc
limit(1)
Upvotes: 1