CODEWITHSUNDEEP
azureazure-resource-managerazure-rm-template
itye1970
itye1970

Reputation: 1995

How can i output a Public IP address from an Arm template only if the allocation method is static?

I am trying to output a Public IP address from an arm template only if the PublicIP being create dis static. If it is Dynamic the output can be ignored.

We have a main template which calls another template to create the virtual machine. The calling template will pass the parameters required to build the machine including whether the Public IP should be static or dynamic using the parameter PIPAllocationMethod.

In the template which builds a vm in the output section I have tried the following code but it doesnt work and returns error as below "Unable to evaluate template output'publicIpAddress' is not valid."

"outputs": {
"publicIpAddress": {
  "value": "[if(equals(parameters('PIPAllocationMethod'),'Static'), reference(variables('primaryPIPAddressName')).ipAddress, parameters('PIPAllocationMethod'))]",
  "type": "string"
}

What I need is to only output the PublicIP Address if is is Static, if it is Dynamic it can be ignored

Help appreciated

Upvotes: 1

Views: 3630

Answers (1)

4c74356b41
4c74356b41

Reputation: 72191

I think you are talking about PublicIP resource, so you have a typo (case sensitivity):

reference(variables('primaryPIPAddressName')).IpAddress

for NIC use this:

reference(variables('primaryPIPAddressName')).ipConfigurations[0].properties.privateIPAddress

in your case i suggest you do this. créate variable with the following value:

"picker": "[if(equals(parameters('PIPAllocationMethod'),'Static'), 'IpAddress', 'publicIPAllocationMethod')]"

and in your output you can do this:

"value": "[reference(variables('primaryPIPAddressName')).[variables('picker')]]"

Upvotes: 3

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