CODEWITHSUNDEEP
androidbuttonbackground-color
Display name
Display name

Reputation: 730

How to get the hex colour of dynamic button

I understand that to set a hex colour of a dynamic button, you can write:

button.setBackgroundColor(Color.parseColor("#FFFFFF"));

But how can I get the colour of the button?

I need this as the button changes colour depending on clicks so I want to write and if statement depending on the colour of the button at the time.

After reading other various answers, they haven't worked for me, unfortunately.

I have tried:

Drawable buttonBackground = button.getBackground();

ColorDrawable buttonColour = (ColorDrawable) button.getBackground();

But this will not allow me to make a comparison using hex codes, e.g.

if (buttonColour == "#FFFFFF"){

//do stuff
}

I have also tried to set the colour in values/colors

<color name="notPresent">#FFFFFF</color>

Then in my code:

String buttonColour= button.getResources().getString(R.color.notPresent);

Then made a comparison using an if statement, but this also fails.

Upvotes: 1

Views: 472

Answers (2)

Bishoy Kamel
Bishoy Kamel

Reputation: 2355

Getting the int color not only button but any View

private Bitmap mBitmap;
private Canvas mCanvas;
private Rect mBounds;

public void initIfNeeded() {
  if(mBitmap == null) {
    mBitmap = Bitmap.createBitmap(1,1, Bitmap.Config.ARGB_8888);
    mCanvas = new Canvas(mBitmap);
    mBounds = new Rect();
  }
}

public int getBackgroundColor(View view) {
  // The actual color, not the id.
  int color = Color.BLACK;

  if(view.getBackground() instanceof ColorDrawable) {
    if(Build.VERSION.SDK_INT < Build.VERSION_CODES.HONEYCOMB) {
      initIfNeeded();

      // If the ColorDrawable makes use of its bounds in the draw method,
      // we may not be able to get the color we want. This is not the usual
      // case before Ice Cream Sandwich (4.0.1 r1).
      // Yet, we change the bounds temporarily, just to be sure that we are
      // successful.
      ColorDrawable colorDrawable = (ColorDrawable)view.getBackground();

      mBounds.set(colorDrawable.getBounds()); // Save the original bounds.
      colorDrawable.setBounds(0, 0, 1, 1); // Change the bounds.

      colorDrawable.draw(mCanvas);
      color = mBitmap.getPixel(0, 0);

      colorDrawable.setBounds(mBounds); // Restore the original bounds.
    }
    else {
      color = ((ColorDrawable)view.getBackground()).getColor();
    }
  }

  return color;
}

Get the hex with the opacity

Hex Format of (#EE111000)

  • first two chars are the opacity --> EE
  • the next is the actual color 111000 refer to this for more about opacity in hex.

covert to hex without losing opacity

  String hexColorWithOpacity = Integer.toHexString(intColorFromPreviosStep);

Upvotes: 0

Anton Kazakov
Anton Kazakov

Reputation: 2774

Button is a view. You can get solid color of view like this 

int color = Color.TRANSPARENT;
Drawable bg = view.getBackground();
if (bg instanceof ColorDrawable)
color = ((ColorDrawable) background).getColor();

Then convert it to color HEX like 

String hexColor = String.format("#%06X", (0xFFFFFF & intColor));

Upvotes: 2

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