Reputation: 97
I have an experimentation of n-back.
I have letter that appear for a maximum of 2.5 sec and then a fixation cross for 0.5 sec.
Right now: When the participant pressed on the keyboard, it ends the routine and go directly to the fixation cross. I have 60 letters so the experimentation would take at max 3 minutes, but it can be less if the participant pressed fast.
What I want : My experimentation should take 3 min at every time. So the fixation cross should stay for more than 0.5 sec if the participant answer fast
Do you have an idea how to do that ?
I was thinking about creating a variable that equals 3. And then if text is 2 sec then 3-2 = 1 so fixation would be 1 sec, but I was not able to write that in my code component
Thanks!!
Upvotes: 1
Views: 178
Reputation: 5683
In your 'trial' routine, I would record the routine starting time. Then in the 'fixation' routine, I would wait until 3 secs have passed since that starting time.
So in 'trial' routine --> Code Component --> 'begin trial' tab:
trial_start = core.monotonicClock.getTime()
Then in the 'fixation' routine --> fixation cross component --> duration, enter:
$trial_start + 3 - core.monotonicClock.getTime() # 3 secs later
Upvotes: 2