CODEWITHSUNDEEP
bash
Mote Zart
Mote Zart

Reputation: 960

Slice array with args from command line - bash

Trying to slice array while taking args from command prompt as the array items. The problem is that the positional parameters for slicing do not work as I expect. How do I slice array taking params from prompt?

./arrays.bash awesome cool strong cute awesome

I want

  arr=$@ 
  echo ${arr[*]:0:2} #awesome cool

I get

  arr=$@ 
  echo ${arr[*]:0:2} # aw

I read the post: How to slice an array in bash but I believe my question is different. Seems to be that the difficulty here is that because I am getting my array values from the command prompt, or not, idk. It does behave as expected when array is included in the script as a variable. This is from learnyoubash so just adjusting the indexes to cut out characters instead of entire values, which does return the correct answer, is not a valid solution to the problem. My solution incorrect but working solution https://github.com/nodeschool/discussions/issues/2241

Upvotes: 5

Views: 3369

Answers (1)

John Kugelman
John Kugelman

Reputation: 361937

To store $@ in an array you must write:

arr=("$@")

Without the parentheses $arr is just a single string.

Upvotes: 7

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