CODEWITHSUNDEEP
error-handlingtimeoutpython-3.6python-asynciotry-except
Jakub Czaplicki
Jakub Czaplicki

Reputation: 1847

try/except not catching future's TimeoutError

Could someone pls explain to me what’s going on here ? I wanted to add a message to the timeout error:

future = asyncio.run_coroutine_threadsafe(do_stuff(), loop=loop)
try:
    return future.result(timeout=3)
except TimeoutError:
    raise TimeoutError("Time out occurred while doing stuff")

future.results() (concurrent.futures._base.py) looks like this :

def result(self, timeout=None):
    # bla bla bla
    else:
        raise TimeoutError()

However when the timeout occurs my try/except clause doesn’t catch the Timeout. In fact

future = asyncio.run_coroutine_threadsafe(do_stuff(), loop=loop)
try:
    return future.result(timeout=3)
except Exception as e:
    log.error(str(e))

shows empty e. WTH?

Upvotes: 3

Views: 936

Answers (1)

Jakub Czaplicki
Jakub Czaplicki

Reputation: 1847

OK. I know. I should be using except asyncio.TimeoutError:, not the base TimeoutError.

Upvotes: 4

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