CODEWITHSUNDEEP
c++c++11templatessfinae
Becks
Becks

Reputation: 468

Static member initialization in a template class

I need to initialize a static bool inside of a template class and I tried to do it like this. The only difference I can see is that I have a constraint on type parameter T but this causes a compilation error, why? How can I solve this?

Code is the following:

template<class T, class = typename enable_if<is_any_integral<T>::value>::type>
class fraction {
    static bool auto_reduce;

    // ...
};

template<class T, class = typename enable_if<is_any_integral<T>::value>::type>
bool fraction<T>::auto_reduce = true;

And the error is:

error: nested name specifier 'fraction<T>::' for declaration does not refer into a class, class template or class template partial specialization
bool fraction<T>::auto_reduce = true;

Upvotes: 2

Views: 696

Answers (1)

max66
max66

Reputation: 66200

Maybe simpler

template<class T, class V>
bool fraction<T, V>::auto_reduce = true;

When you write 

template<class T, class = typename enable_if<is_any_integral<T>::value>::type>
class fraction

you say that fraction is a class with two type template paramenters; the std::enable_if if part is useful to assign a default value to the second parameter (and to permit the enable/not enable SFINAE works) but fraction is and remain a template class with two parameters, you have to cite both and there is no need to repeat the enable/not enable/default part for second parameter initializing auto_reduce.

Upvotes: 2

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