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arrayslinuxbashshellawk
enodmilvado
enodmilvado

Reputation: 483

bash array + how to set variable in bash array

we set the "list" variable with sdb - sdz range

# MAX=z
# list=$(eval echo sd{b..$MAX})
# echo $list
sdb sdc sdd sde sdf sdg sdh sdi sdj sdk sdl sdm sdn sdo sdp sdq sdr sds sdt sdu sdv sdw sdx sdy sdz

until now its ok

now we set the $list in array as the follwing

#array=( echo $list )

but when we print the first value of the array we get "echo"

#echo ${array[0]}
echo

what is wrong here?

expected results:

#echo ${array[0]}
sdb


#echo ${array[1]}
sdc

#echo ${array[2]}
sdc

or

# echo  "${list[counter++]}"

Upvotes: 0

Views: 354

Answers (1)

PesaThe
PesaThe

Reputation: 7509

$ max=z
$ list=( $(eval echo sd{b..$max}) )
$ echo "${list[*]}"
sdb sdc sdd sde sdf sdg sdh sdi sdj sdk sdl sdm sdn sdo sdp sdq sdr sds sdt sdu sdv sdw sdx sdy sdz
$ echo "${list[1]}"
sdc

Upvotes: 1

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