CODEWITHSUNDEEP
python-2.7numpy
uhoh
uhoh

Reputation: 3745

np.diff(np.signbit()) no longer finds zero crossings, better way?

This answer is what I'm looking for, but since boolean subtraction has been depreciated it no longer works. Is there a better way?

A   = np.array([[-2, -1,  1], 
                [-1,  0,  1], 
                [-1,  1,  2]], dtype=float)

zcs = np.diff(np.signbit(A), axis=1)     # find zero crossings in each row - now fails

generates:

Traceback (most recent call last):
  File "/Users/david/Documents/wow.py", line 4, in <module>
    zcs = np.diff(np.signbit(A), axis=1)     # now fails
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/numpy/lib/function_base.py", line 1926, in diff
    return a[slice1]-a[slice2]

TypeError: numpy boolean subtract, the `-` operator, is deprecated, use the bitwise_xor, the `^` operator, or the logical_xor function instead.

Upvotes: 0

Views: 355

Answers (1)

Daniel F
Daniel F

Reputation: 14399

This is apparently fixed in 1.14.0, but as a quick fix explicit type casting:

zcs = np.diff(np.signbit(A).astype(int), axis=1)

should work.

Upvotes: 1

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