CODEWITHSUNDEEP
pythondictionaryordereddictionary
JustCurious
JustCurious

Reputation: 111

Ordered Dictionary (sorted) in Python

I have below list of dictionary. I want to get an ordered dictionary on the basis of server_resource_name. I followed How to correctly sort a string with a number inside? but I wonder if there is something more pythonic? 

ls = [
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",      
        "server_resource_name": "i10_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i11_instance"
    },

    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i7_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",      
        "server_resource_name": "i8_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i9_instance"
    }
]

I am looking for output to be like below

ls = [
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",      
        "server_resource_name": "i7_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i8_instance"
    },

    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i9_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",      
        "server_resource_name": "i10_instance"
    },
    {
        "flavor": "m1.small",
        "internal_network_name": "inner-net",
        "key_name": "tmp_key",
        "server_resource_name": "i11_instance"
    }
]

What I tried

test1 = []
for i in ls:
     i['server_resource_name']
     test1.append(i['server_resource_name'])
import re
def natural_key(string_):
    return [int(s) if s.isdigit() else s for s in re.split(r'(\d+)', string_)]

This gives me the sorted result in test2. How do I get the ls now to be in sorted fashion? 

print("-->", sorted(test1, key=natural_key))

Upvotes: 0

Views: 112

Answers (2)

Vikram Patil
Vikram Patil

Reputation: 661

May be you can try following:

import re
p=re.compile('(\d+)')
ls.sort(key=lambda x: int(p.findall(x['server_resource_name'])[0] ))

Upvotes: 0

Boris
Boris

Reputation: 166

Thats works maybe there are better way to do it

# Thats for parse number of instance
# print(int(re.findall(r'\d+', ls[0]["server_resource_name"])[0]))
sorted_ls = sorted(ls, key=lambda x: int(re.findall(r'\d+', x["server_resource_name"])[0]))
print(sorted_ls)

Upvotes: 3

Related Questions