CODEWITHSUNDEEP
javascriptnode.js
Mahesh Jagdale
Mahesh Jagdale

Reputation: 174

how to export function in nodejs

i am new in nodejs,i need to export function in nodejs
db_function.js file 

var mysql = require('mysql'); 
var config  = require('./config.js');
var con = config.conn;

exports.is_valid_IP = {
 function(IP,callback)
  {
    con.connect(function(err) {
      if (err) throw err;
      con.query("SELECT * FROM server_master", function (err, result, fields) {
        if (err) throw err;
        callback(result);
      });
    });
  }
};

app.js file 

  app.get('/test',function(req,res){
  var IP = 1;
  db.is_valid_IP(IP,function(result){
    console.log(result);
  });
});

It Show error Cannot call method 'connect' of undefined

Upvotes: 1

Views: 3877

Answers (3)

Yuci
Yuci

Reputation: 30079

Let's simplify the issue, as the title of the question suggests, "how to export function in nodejs". If we only consider how to export function in Node.js, we can do as below:

./db_function.js (We export function isValidIp):

'use strict';

module.exports.isValidIp = function(ip, callback) {
    console.log("Check if IP is valid.");
    callback();
};

./app.js

'use strict';

var db = require('./db_function');
// require() returns the object that module.exports references

db.isValidIp('127.0.0.1', function(){
    console.log('Called back.');
});

Run it with command node app.js, you'll get:

Check if IP is valid.
Called back.

One caveat

./db_function.js (This version does not work):

'use strict';

exports = { 
    isValidIp: function(ip, callback) {
        console.log("Check if IP is valid.");
        callback();
    }
};

You'll get TypeError:

TypeError: db.isValidIp is not a function

That is because require() return module.exports, rather than exports. exports is just a shorthand of module.exports. If you point exports to a different object, you should update module.exports as well. The following version will work:

'use strict';

exports = { 
    isValidIp: function(ip, callback) {
        console.log("Check if IP is valid.");
        callback();
    }
};

module.exports = exports;

Upvotes: 0

Adelin
Adelin

Reputation: 8199

Let me sum up the comments:

You export correctly. That's not where your problem lies

The issue occurs due to the fact that, in db_function.js, con is not defined.

Even if you declare it in app.js, javascript will correctly isolate the two contexts (app.js from db_function.js).

We talk about different files here, but the context preservation can occur even in the same files

var functionOne = function(){
   var con = 1;
}
console.log(con) // undefined err, because con is declared inside the function

even if you call the function

var functionOne = function(){
   var con = 1;
}
functionOne();
console.log(con) // undefined err, because con is long gone as soon as function returns

con will live only until the function returns.

if you want to tell is_valid_IP what connection to use, you can simply update your code as follows:

db_function.js file

exports.is_valid_IP = {
 function(IP,con,callback)
  {
    con.connect(function(err) {
      if (err) throw err;
      con.query("SELECT * FROM server_master", function (err, result, fields) {
        if (err) throw err;
        callback(result);
      });
    });
  }
};

And then use it in app.js file as follows:

app.get('/test',function(req,res){
  var IP = 1;
  db.is_valid_IP(IP,con,function(result){
    console.log(result);
  });
});

Upvotes: 2

suresh kumar
suresh kumar

Reputation: 167

You can export like this:

enter code here
var funName = function() {
}
module.exports = funName;

Upvotes: 5

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