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pythondictionaryif-statementdefault-value
Jonathan Allen Grant
Jonathan Allen Grant

Reputation: 3668

Using dictionary to populate default variables in methods as a one-liner in python2

I want to pass in a value from a dictionary - only if it exists - to my function. If the key, value doesn't exist in this dictionary, I want the method to use its default.

For example, with method m:

def m(a=1, b=2, c=3)

And dictionary d:

d = {"a": 5}

I want to pass in the values of the dictionary into the method if they exist in a one liner. Something like this:

m(a=d["a"] if d.get("a"), b=d["b"] if d.get("b"), c=d["c"] if d.get("c"))

Is there a way to do this in python2 as a one liner? Or am I stuck using multiple if conditions like this:

if d.get("a") and d.get("b") and d.get("c"):
    m(a=d["a"], b=d["b"], c=d["c"])
elif d.get("a") and d.get("b"):
    m(a=d["a"], b=d["b"])
elif d.get("a"):
    m(a=d["a"])
# ...and so on

Upvotes: 0

Views: 47

Answers (1)

Jonathan Allen Grant
Jonathan Allen Grant

Reputation: 3668

If I call m(**d) it works. This is just what I was looking for.

Upvotes: 1

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