Reputation: 15
I defined the form in the share-config-custom.xml
configuration file and I have a home.ftl
page. How can I associate a form definition in the configuration file with the home.ftl
page?
Upvotes: 1
Views: 257
Reputation: 513
You can retrieve configured form by the /components/form
webscript, so you can use a javascript controller to inject your form in your page as mentioned in the previous answer by @vikash or you can use Spring surf to create the page, for that you can check Alfresco documentation Surf Pages.
In the definition page, make /components/form
as url and url parameters as properties, as mentioned in the following example
<?xml version="1.0" encoding="UTF-8"?>
<component>
<url>/components/form</url>
<properties>
<itemKind>type</itemKind>
<itemId>contentType</itemId>
<mode>edit</mode>
<formUI>true</formUI>
<submitType>json</submitType>
<showCaption>true</showCaption>
<showCancelButton>true</showCancelButton>
</properties>
</component>
If you want to get a form for a configured type you should make type
in itemKind
and type name in itemId
(cm:xxx)
Upvotes: 1
Reputation: 1348
You can open the share form using content-type To open form
function render(htmlPageId) {
var contentType = "content_type";
var formHtmlId = htmlPageId+ "-metadata-form";
var url = YAHOO.lang
.substitute(
"{serviceContext}components/form"
+ "?itemKind=type&itemId={itemId}&mode=create&submitType=json"
+ "&formId={formId}&showCancelButton=true&htmlid={htmlid}"
+ "&destination={destination}&siteId={siteId}&containerId={containerId}&uploadDirectory={uploadDirectory}",
{
serviceContext : Alfresco.constants.URL_SERVICECONTEXT,
itemId : contentType,
itemKind : "model",
formId : "upload-folder",
destination : "workspace://SpacesStore/e9d60c89-823a-4e3e-abb2-522e59a09d0f",
siteId : "production",
containerId : "documentLibrary",
uploadDirectory : "/GM",
htmlid : formHtmlId
});
Alfresco.util.Ajax.request({
url : url,
responseContentType : "html",
execScripts : true,
successCallback : {
fn : function(response) {
var formNode = YAHOO.util.Dom.get(formHtmlId);
formNode.innerHTML = response.serverResponse.responseText;
},
scope : this
},
failureCallback : {
fn : function(response) {
Alfresco.logger.debug("onContentTypeChange failureCallback",
arguments);
},
scope : this
}
});
}
Pass your content type here in - contentType which type of form you wanted to open.
and
var formNode = YAHOO.util.Dom.get(formHtmlId);
formNode.innerHTML = response.serverResponse.responseText;
formHtmlId is the id of your html component like
<div id="${el}-renderForm" onload="render(htmlID)">
</div>
pass your current htmlId in this funtion.
Upvotes: 0