Reputation: 1596
I got a pandas dataframe where two columns correspond to names of people. The columns are related and the same name means same person. I want to assign the category code such that it is valid for the whole "name" space.
For example my data frame is
df = pd.DataFrame({"P1":["a","b","c","a"], "P2":["b","c","d","c"]})
>>> df
P1 P2
0 a b
1 b c
2 c d
3 a c
I want it to be replaced by the corresponding category codes, such that
>>> df
P1 P2
0 1 2
1 2 3
2 3 4
3 1 3
The categories are in fact derived from the concatenated array ["a","b","c","d"] and applied on individual columns seperatly. How can I achive this ?.
Upvotes: 4
Views: 1616
Reputation: 863351
Use:
print (df.stack().rank(method='dense').astype(int).unstack())
P1 P2
0 1 2
1 2 3
2 3 4
3 1 3
EDIT:
For more general solution I used another answer, because problem with duplicates in index:
df = pd.DataFrame({"P1":["a","b","c","a"],
"P2":["b","c","d","c"],
"A":[3,4,5,6]}, index=[2,2,3,3])
print (df)
A P1 P2
2 3 a b
2 4 b c
3 5 c d
3 6 a c
cols = ['P1','P2']
df[cols] = (pd.factorize(df[cols].values.ravel())[0]+1).reshape(-1, len(cols))
print (df)
A P1 P2
2 3 1 2
2 4 2 3
3 5 3 4
3 6 1 3
Upvotes: 2
Reputation: 77017
You can do
In [465]: pd.DataFrame((pd.factorize(df.values.ravel())[0]+1).reshape(df.shape),
columns=df.columns)
Out[465]:
P1 P2
0 1 2
1 2 3
2 3 4
3 1 3
Upvotes: 2