CODEWITHSUNDEEP
pythonbeautifulsoup
user3337705
user3337705

Reputation:

Python beautiful soup syntax error

I'm using an example I found that extracts links from an webpage

from BeautifulSoup import BeautifulSoup
import urllib2
import re

html_page = urllib2.urlopen("http://arstechnica.com")
soup = BeautifulSoup(html_page)
for link in soup.findAll('a', attrs={'href': re.compile("^http://")}):
print link.get('href')

I get:

File "html_test.py", line 9
    print link.get('href')
             ^
SyntaxError: invalid syntax

I've installed BeautifulSoup with pip to no success.

Upvotes: 0

Views: 3343

Answers (1)

Ajax1234
Ajax1234

Reputation: 71451

Instead of 

from BeautifulSoup import BeautifulSoup

use:

from bs4 import BeautifulSoup

Also, in Python3, print is a function, not a statement:

print(link.get('href'))

Upvotes: 1

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