Reputation: 803
I have a tensor as follows and a numpy 2D array
k = 1
mat = np.array([[1,2],[3,4],[5,6]])
for row in mat:
values_zero, indices_zero = tf.nn.top_k(row, len(row) - k)
row[indices_zero] = 0 #????
I want to assign the elements in that row to be zero at those indices. However I can't index a tensor and assign to it as well. I have tried using the tf.gather function but how can I do an assignment? I want to keep it as a tensor and then run it in a session at the end if that is possible.
Upvotes: 2
Views: 6455
Reputation: 61325
One way to do this is by advanced indexing:
In [87]: k = 1
In [88]: mat = np.array([[1,2],[3,4],[5,6]])
# `sess` is tf.InteractiveSession()
In [89]: vals, idxs = sess.run(tf.nn.top_k(mat, k=1))
In [90]: idxs
Out[90]:
array([[1],
[1],
[1]], dtype=int32)
In [91]: mat[:, np.squeeze(idxs)[0]] = 0
In [92]: mat
Out[92]:
array([[1, 0],
[3, 0],
[5, 0]])
Upvotes: 0
Reputation: 2433
I guess you are trying to mask the maximum in each row to zero? If so, I would do it like this. The idea is to create the tensor by construction rather than assignment.
import numpy as np
import tensorflow as tf
mat = np.array([[1, 2], [3, 4], [5, 6]])
# All tensorflow from here
tmat = tf.convert_to_tensor(mat)
# Get index of maximum
max_inds = tf.argmax(mat, axis=1)
# Create an array of column indices in each row
shape = tmat.get_shape()
inds = tf.range(0, shape[1], dtype=max_inds.dtype)[None, :]
# Create boolean mask of maximums
bmask = tf.equal(inds, max_inds[:, None])
# Convert boolean mask to ones and zeros
imask = tf.where(bmask, tf.zeros_like(tmat), tf.ones_like(tmat))
# Create new tensor that is masked with maximums set to zer0
newmat = tmat * imask
with tf.Session() as sess:
print(newmat.eval())
which outputs
[[1 0]
[3 0]
[5 0]]
Upvotes: 4