CODEWITHSUNDEEP
phpandroidjson
Arturo Aguilera
Arturo Aguilera

Reputation: 15

How to get the JSON Object in PHP from Android OKHttp

I have my OkHttp code here (i'm working in Android)

    void postRequest(String postUrl, String postBody) throws IOException {
        OkHttpClient client = new OkHttpClient();
        RequestBody body = RequestBody.create(JSON,postBody);
        Request request = new Request.Builder()
            .url(postUrl)
            .post(body)
            .build();

    client.newCall(request).enqueue(new Callback() {
        @Override
        public void onFailure(Call call, IOException e) {
            call.cancel();
        }

        @Override
        public void onResponse(Call call, Response response) throws IOException {
            Log.d("TAG",response.body().string());
        }
    });
}

And this is my PHP part

<?php
    header("Content-type: application/json; charset=utf-8");

    include("conexion.php");

    $nombre = $_POST["nombre"];
    $apellidoPaterno = $_POST['apellidoPaterno'];
    $apellidoMaterno = $_POST['apellidoMaterno'];
    $direccion = $_POST['direccion'];
    $redesSociales = $_POST['redesSociales'];
    $telefono = $_POST['telefono'];
    $nombreUsuario = $_POST['nombreUsuario'];
    $contrasena = $_POST['contrasenaUsuario'];

?>

I want to obtain the values that are passing through my JSON, but when I use $_POST they end with no values. I've tried with the API of reqres and it does send the information.

Any help is appreciated, thanks.

Upvotes: 0

Views: 689

Answers (2)

Jeff
Jeff

Reputation: 6943

Following your and my comments you could do the following:

<?php
// header("Content-type: application/json; charset=utf-8"); // not really needed here for now
    include("conexion.php");
    $fgc = file_get_contents("php://input");
    $json = json_decode($fgc, true);
    // now you've got all your values in $json:
    $nombre = $json["nombre"];

alternatively you could do:

    $json = json_decode($fgc);
    // now you've got all your values as an object in $json:
    $nombre = $json->nombre;

further reading: http://php.net/manual/de/wrappers.php.php#wrappers.php.input

Upvotes: 1

Carlos Quintero
Carlos Quintero

Reputation: 268

try this:

//this only you use to issue a response in json format from your php to android
//header("Content-type: application/json; charset=utf-8");

include("conexion.php");

//The following lines serve to receive a json and transform them to the variables
$data = json_decode($_POST);

$nombre = $data->nombre;
$apellidoPaterno = $data->apellidoPaterno;
$apellidoMaterno = $data->apellidoMaterno;
$direccion = $data->direccion;
$redesSociales = $data->redesSociales;
$telefono = $data->telefono;
$nombreUsuario = $data->nombreUsuario;
$contrasena = $data->contrasenaUsuario;

Of course everything depends on how you are arming the body of the post sent, on the other hand if you are making a post request from android to your php, you do not need to convert the variables to json, just pass the body and already.

You must convert to JSON only the answers of your php towards android.

SAMPLE: https://ideone.com/x2ENdd

Upvotes: 0

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