Reputation: 402
I have these documents in my collection
{
id:1,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
},
{
id:2,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
},
{
id:3,
small:[{k:'A',v:1},{k:'B',v:2},{k:'D',v:3}],
big:[{k:'A',v:2},{k:'B',v:3},{k:'C',v:1},{k:'D',v:4}]
}
Now, I want to get the sum for each key in both lists. I want my output to look like this:
{k:'A',small:3, big:6},
{k:'B',small:6, big:9},
{k:'D',small:9, big:12}
Notice that the output did not contain the key 'C'. This is because I only want to output the keys that are existing in the 'small' list. What mongodb functions should I use for this?
Thanks!
Upvotes: 0
Views: 22
Reputation: 49975
Try below aggregation:
db.col.aggregate([
{ $unwind: "$small" },
{ $unwind: "$big" },
{ $redact: {
$cond: {
if: { $eq: [ "$small.k", "$big.k" ] },
then: "$$KEEP",
else: "$$PRUNE"
}
}
},
{
$group: { _id: "$small.k", small: { $sum: "$small.v" }, big: { $sum: "$big.v" } }
},
{
$sort: { "_id": 1 }
}
])
In general we need to have only one small
and big
in each document (that's why double $unwind). Then we want to keep only documents where keys are equal. That's the moment where C
is filtered out - has no pair in small
and we're utilizing $redact for that. Aggregation is just a $group with $sum.
Upvotes: 1