CODEWITHSUNDEEP
pythonmathlinear-algebra
Moccar
Moccar

Reputation: 99

Linear equation without NumPy

I am relatively new to Python and programming in general. At the moment, I am doing Repl.it student courses. The statement/instruction is as follows:

Write a program that solves a linear equation ax = b in integers. Given two integers, a and b, where a may be zero, print a single integer root if it exists and print "no solution" or "many solutions" otherwise.

Example input: a = 1, b = -2

Example output: -2

My code so far looks like this:

a = int(input())
b = int(input())

if a==0:
  print("many solutions")
elif (b == 0):
  print (b)
elif (a!=0):
  x=int(b/a)
  if x!=0:
     print(x)
  elif x==0:
     print("no solution")

It fails when a = 0 and b = 7. I do not know why though. Any answers will be much appreciated.

Edit: Thanks for the answers, they were helpful. I have managed to come up with a solution that worked.

Upvotes: 0

Views: 5047

Answers (1)

Moccar
Moccar

Reputation: 99

I found this to work properly thanks to some of the comments.

a = int(input())
b = int(input())

if a == 0:
  if b == 0:
    print('many solutions')
  else:
    print('no solution')
elif b % a == 0:
  print(b // a)
else:
  print('no solution')

Upvotes: 1

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