CODEWITHSUNDEEP
c++operator-overloadingmetaprogrammingparameterization
meta-cpp
meta-cpp

Reputation: 61

meta multiple operator overloading

The question is if I can find a way to make a parametrized overloading of an operator i.e. instead of 

template <class T>
class A
{
   private:
       T m_var;
   public:
       operator T () const { return m_var; }
       const A operator+ ( const A& r_var ) const { return m_var + r_var; }
       const A operator- ( const A& r_var ) const { return m_var - r_var; }
       const A operator* ( const A& r_var ) const { return m_var * r_var; }
       const A operator/ ( const A& r_var ) const { return m_var / r_var; }
   ...........
}

to have something like this

template <class T>
class A
{
   private:
       T m_var;
   public:
       operator T () const { return m_var; }
       const A operator 'X' ( const A& r_var ) const { return m_var 'X' r_var; }

   ...........
}

where 'X' will take values +, -, *, /, and in this way to avoid repetition of the same pattern code. Thanks in advance.

Upvotes: 2

Views: 164

Answers (2)

Puppy
Puppy

Reputation: 146940

This isn't possible within templates. You will need to write a macro.

Also, you should not return a const rvalue, because it's perfectly legal to call non-const methods on rvalues of class type.

Upvotes: 0

rymurr
rymurr

Reputation: 444

Check out boost::operators. It requires += and *= to be defined by you. The rest(+,-,*,/,-=,/=) are defined by the library. It also works for binary operators.

Upvotes: 2

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