CODEWITHSUNDEEP
javaandroidregex
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Reputation: 13

What's wrong with this regex?

I need to match Twitter-Hashtags within an Android-App, but my code doesn't seem to do what it's supposed to. What I came up with is:

ArrayList<String> tags = new ArrayList<String>(0);
Pattern p = Pattern.compile("\b#[a-z]+", Pattern.CASE_INSENSITIVE);
Matcher m = p.matcher(tweet); // tweet contains the tweet as a String
while(m.find()){
    tags.add(m.group());
}

The variable tweet contains a regular tweet including hashtags - but find() doesn't trigger. So I guess my regular expression is wrong.

Upvotes: 1

Views: 1373

Answers (2)

Tim Pietzcker
Tim Pietzcker

Reputation: 336138

Your regex fails because of the \b word boundary anchor. This anchor only matches between a non-word character and a word-character (alphanumeric character). So putting it directly in front of the # causes the regex to fail unless there is an alphanumeric character before the #! Your regex would match a hashtag in foobarfoo#hashtag blahblahblah but not in foobarfoo #hashtag blahblahblah.

Use #\w+ instead, and remember, inside a string, you need to double the backslashes: 

Pattern p = Pattern.compile("#\\w+");

Upvotes: 3

Nick Campion
Nick Campion

Reputation: 10479

Your pattern should be "#(\\w+)" if you are trying to just match the hash tag. Using this and the tweet "retweet pizza to #pizzahut", doing m.group() would give "#pizzahut" and m.group(1) would give "pizzahut".

Edit: Note, the html display is messing with the backslashes for escape, you'll need to have two for the w in your string literal in Java.

Upvotes: 2

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