Reputation: 339
I want to use the Charts.js Library and make the data displayed in the graph dependent on what a user has entered.
Right now I am not quite sure how to get the data in the right format so that I can use if for the library.
Currently I have a problem when combining the labels and values so that it matches the right index for the right label. I am having a table with two values ( A Month (Specified as Jan,Feb,Mar,Apr.etc.) and a numeric Value)
Now I need to combine months that appear twice and add the values associated with each month. I dont really know if I should use a 2d Array or 2 arrays for this. For example
var labels = ["Jan 17", "Jan 17", "Feb 17", "Mar 17", "Mar 17"];
var values = [10,10,25,40,100];
becomes
var newlabels = ["Jan 17", "Feb 17", "Mar 17"];
var newvalues = [20,25,140];
or as 2D Array:
var graphdata = [["Jan 17", 10],["Jan 17",10],["Feb 17",25],["Mar 17",40],["Mar 17",100]];
becomes
var newgraphData =[["Jan 17", 20],["Feb 17",25],["Mar 17",140]];
Either way is fine but I dont know which to use. Also I wouldn't quite know how to get the data in a 2d Array with jQuery selectors and the .map() function.
I was thinking of using the .map() and .reduce() function with a loop to go through each index but I cant quite seem to figure out how to do it.
Upvotes: 1
Views: 1655
Reputation: 135197
Here's another approach that aims to deconstruct the problem into smaller parts. Once we have a couple functions to transform data in a high-level way, assembling the final result becomes a trivial task.
We can start with a way to combine your two lists in a zipper-like fashion, using zip
const None =
Symbol ()
const zip = ([ x = None, ...xs ], [ y = None, ...ys ]) =>
x === None || y === None
? []
: [ [ x, y ] ] .concat (zip (xs, ys))
const labels =
[ "Jan 17", "Jan 17", "Feb 17", "Mar 17", "Mar 17" ]
const values =
[ 10, 10, 25, 40, 100 ]
console.log (zip (labels, values))
// [ [ 'Jan 17', 10 ]
// , [ 'Jan 17', 10 ]
// , [ 'Feb 17', 25 ]
// , [ 'Mar 17', 40 ]
// , [ 'Mar 17', 100 ]
// ]
With a list of [ key, value ]
pairs, we can create a Map that groups values by key
. Maps are lightning fast thanks to logarithmic search. JavaScript gives us Map, so when applicable, it's best to use it instead of a plain Object. At the very least, avoid using Array.prototype.indexOf
like one answer suggests as it uses linear search and not suitable for larger data sets.
const group = (xs = []) =>
xs.reduce ((acc, [ key, value ]) =>
acc.has (key)
? acc.set (key, value + acc.get (key))
: acc.set (key, value),
new Map ())
console.log (group (zip (labels, values)))
// => Map { 'Jan 17' => 20, 'Feb 17' => 25, 'Mar 17' => 140 }
Lastly, we can convert from a Map to your desired output type using Array.from, Map.prototype.entries
const main = (labels = [], values = []) =>
Array.from (group (zip (labels, values)) .entries ())
Here's a functioning example
const None =
Symbol ()
const zip = ([ x = None, ...xs ], [ y = None, ...ys ]) =>
x === None || y === None
? []
: [ [ x, y ] ] .concat (zip (xs, ys))
const group = (xs = []) =>
xs.reduce ((acc, [ key, value ]) =>
acc.has (key)
? acc.set (key, value + acc.get (key))
: acc.set (key, value),
new Map ())
const main = (labels = [], values = []) =>
Array.from (group (zip (labels, values)) .entries ())
const labels =
[ "Jan 17", "Jan 17", "Feb 17", "Mar 17", "Mar 17" ]
const values =
[ 10, 10, 25, 40, 100 ]
console.log (main (labels, values))
// [ [ 'Jan 17', 20 ]
// , [ 'Feb 17', 25 ]
// , [ 'Mar 17', 140 ]
// ]
Upvotes: 1
Reputation: 7973
const labels = ["Jan 17", "Jan 17", "Feb 17", "Mar 17", "Mar 17"];
const values = [10,10,25,40,100];
const result = labels.map((label, i) => ({label, value: values[i]}));
const grouped = []
result.forEach(o => {
if (!this[o.label]) {
this[o.label] = { label: o.label, value: 0 };
grouped.push(this[o.label]);
}
this[o.label].value += o.value;
}, {});
console.log(grouped) // [ { label: 'Jan 17', value: 20 }, { label: 'Feb 17', value: 25 }, { label: 'Mar 17', value: 140 } ]
Upvotes: 1
Reputation: 1486
Try this. You will get the formatted data in the arrays rLabels
and rValues
.
var labels = ["Jan 17", "Jan 17", "Feb 17", "Mar 17", "Mar 17"]
, values = [10, 10, 25, 40, 100]
, rLabels = []
, rValues = [];
for (var i = 0; i < labels.length; i++) {
var label = labels[i];
var ind = rLabels.indexOf(label);
if (ind == -1) {
rLabels.push(label);
rValues.push(values[i]);
} else {
rValues[ind] += values[i];
}
}
Upvotes: 1