CODEWITHSUNDEEP
pythonnumpy
BjkOcean
BjkOcean

Reputation: 55

If condition cannot evaluate multiple "True"s - Python

I have 3D numpy array called BNodeVal. Currently its size is (1,1,16), but it can be bigger than this. I am trying to evaluate an if condition using this 3D array and 3 coordinates coord_x , coord_y, coord_z.

BNodeVal = [[[ 0. 1. 15. 0. 0. 13.4 1.77 15.9 1.77 37.391 1.03 40.931 39.161 0.5402 0. 0. ]]]

Below is that portion of the code that is not working correctly: 

for j in range(int(np.amax(BNodeval[i, :, 1]))):
    print("x = ", coord_x, "\ny =", coord_y, "\nz =", coord_z)
    print("3 = ", BNodeval[i][j][2], "\n4 =", BNodeval[i][j][3], "\n5 =", BNodeval[i][j][4])
    print(np.isclose(coord_x, BNodeval[i][j][2]))
    print(np.isclose(coord_y, BNodeval[i][j][3]))
    print(np.isclose(coord_z, BNodeval[i][j][4]))

    if np.isclose(coord_x, BNodeval[i][j][2]) and \
       np.isclose(coord_y, BNodeval[i][j][3]) and \
       np.isclose(coord_x, BNodeval[i][j][4]) :  # 1 - 1
        print("# 1 - 1")
    else:
        print('# 1 - 2")

This is what it is printing : 

x =  15.0 
y = 0.0 
z = 0.0
3 =  15.0 
4 = 0.0 
5 = 0.0
True
True
True
# 1 - 2

However, if i only use one of the np.isclose terms, it just work fine and print # 1 - 2 instead. Any suggestion is appreciated.

Upvotes: 0

Views: 62

Answers (1)

Elazar
Elazar

Reputation: 21625

The last test is wrong. You are printing:

print(np.isclose(coord_z, BNodeval[i][j][4]))

But testing:

np.isclose(coord_x, BNodeval[i][j][4])
                 ^ should be z

Upvotes: 1

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