CODEWITHSUNDEEP
c++templatestypedef
user7747610
user7747610

Reputation:

C++ typedef for templated class

What's the best way to create an alias for a templated class in C++?

template<typename T>
class Dummy1
{
public:
    Dummy1(T var) : myVar1(var) {
    }
    ~Dummy1() {
    }
private:
    T myVar1;
};

C style would be:

typedef Dummy1<int> DummyInt;

In C++, as far as I know, I would write:

class DummyInt : public Dummy1<int> 
{
    DummyInt(int a) : Dummy1<int>(a) { }
    ~DummyInt() { }
}

Is there a better/shorter way? Cause this way when I inherit from the base, I have to declare the constructors every time.

I need an alias for Dummy1<int> otherwise I need to use the template option through the entire code (like pointers and references). But I would like to not do this.

Upvotes: 2

Views: 2825

Answers (3)

StoryTeller - Unslander Monica
StoryTeller - Unslander Monica

Reputation: 170065

If you just must use inheritance then you can avoid repeating the constructors in and onward by just inheriting them:

struct DummyInt : Dummy1<int> {
  using Dummy1::Dummy1;
};

Otherwise, just use an alias like you do. If you want it to not be the "C way" you can employ the modern C++ style:

using DummyInt = Dummy1<int>;

Upvotes: 8

Serve Laurijssen
Serve Laurijssen

Reputation: 9733

You can just as well use a typedef or a using in C++

typedef Dummy1<int> DummyInt;
using DummyInt = Dummy1<int>;

You dont see typedef anymore in modern C++ code IMO.

Upvotes: 4

Demosthenes
Demosthenes

Reputation: 1535

I prefer (C++11 and after):

using DummyInt = Dummy1<int>;

No reason not to use an alias here, in my opinion.

Upvotes: 3

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