CODEWITHSUNDEEP
regexlinuxsed
user3139545
user3139545

Reputation: 7374

Add a underscore to every regexp match in linux

Given 100 XML files that can contain UUIDs I want to find all UUIDs and add an underscore to the beginning of that UUID. The content of the XML file can look different but an example is:

<bpmndi:BPMNEdge bpmnElement="627b6548-aa19-47c6-a87c-31017810a934-_jbpm-unique-3490" >

I want to transform this to:

<bpmndi:BPMNEdge bpmnElement="_627b6548-aa19-47c6-a87c-31017810a934-_jbpm-unique-3490" >

What I have so far is a regexp to find all UUIDs:

ag [0-9a-f]{8}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}

The problem is that most other articles I have found either is for how to start the line that contains a match with some character or to replace the whole line. I just want to add a character to the match.

Upvotes: 1

Views: 51

Answers (1)

anubhava
anubhava

Reputation: 784878

Your regex is correct. You can use that in sed as:

sed -i.bak -E 's/[0-9a-f]{8}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{4}-[0-9a-f]{12}/_&/g' file

Replacement expression _& will prefix matched text with underscore.

Upvotes: 1

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