CODEWITHSUNDEEP
javascriptjquery
GeekyNerd
GeekyNerd

Reputation: 1

How to make this kind of array in jquery?

i am trying to building dynamically an array of empty elements. This is what i have tried so far. 

aData.length=5;
var noOFSeries = [];
    for (var i = 1; i <= aData.length - 1; i++) {
        noOFSeries.push([]);
    }

I want this kind of output [], [], [], [] so that i can put in jqplot.

$.jqplot('barchartReqCat', [chartData, [], [], [], []], options);

replace to

$.jqplot('barchartReqCat', [chartData, noOFSeries], options);

Thanks for your help.

Upvotes: 0

Views: 58

Answers (3)

KL_
KL_

Reputation: 1513

There you have some ways:
arr1 filled with .map();
arr2 filled with .fill(); and
arr3 with loop.

var arr1 = [1, 2, 3, 4].map(function(value) {
  return [];
});
console.log(arr1);

var arr2 = new Array(4).fill([]);
console.log(arr2);

var arr3 = [];
var length = 5;
for(var i = 0; i < 4; i++) arr3.push([]);

console.log(arr3);

Upvotes: 2

Serge K.
Serge K.

Reputation: 5323

You could use spread operator or, if you want backward compatibility, you can use a new array (myArr in my example):

var aData = {
    length: 5
  },
  noOFSeries = [],
  chartData = [1, 2, 3, 4, 5]

for (var i = 1; i <= aData.length - 1; i++) {
  noOFSeries.push([]);
}

$.jqplot('barchartReqCat', [chartData, ...noOFSeries], options);

var myArr = [chartData].concat(noOFSeries);
$.jqplot('barchartReqCat', myArr, options);

Upvotes: 1

mdatsev
mdatsev

Reputation: 3879

You can use Array.prototype.fill like this:

let noOfSeries = Array(5).fill([]);

Upvotes: 2

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