CODEWITHSUNDEEP
cgcc
Peter K.
Peter K.

Reputation: 134

How to declare variable in function arguments

I need to declare a variable inside function arguments. Please advice the syntax to use?

I've got something like this:

#include <stdio.h>

int foo (int *a)
{
   printf ("%d\n", *a);
}

int main (void)
{
   foo (&(int){int a=1});
   return 0;
}

And GCC fails with the message:

$ gcc a.c
a.c: In function 'main':
a.c:10: error: expected expression before '{' token

As an option I can put use not named variable like this (same question at russian version of Stack Overflow):

foo(&(int) { 1 });

and it works, but it is interesting why compiler accept {1} but does not accept {int a=1}

Upvotes: 0

Views: 107

Answers (1)

Lundin
Lundin

Reputation: 213689

You can use compound literal - I suspect that's what you tried, you almost got it right:

foo (&(int){1});

This is by no means a "constant", I don't know how you got that idea.

Note that a compound literal only have local ("automatic") storage duration - if the calling block goes out of scope, so does the compound literal.

Upvotes: 3

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