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pythonvalidationdictionaryvoluptuous
Ray Salemi
Ray Salemi

Reputation: 5913

Voluptuous: Validate dicts within dicts

I'd like to validate the following YAML file defines a defaultdict that contains two dicts named dev and sha. 

 !!python/object/apply:collections.defaultdict
 args:
 - !!python/name:builtins.dict ''
 dictitems:
   dev:
     sha: 5b7
     url: /path/to/here
   shared:
     sha: 58a
     url: /path/to/there

using yaml.load() (safe_load() leads to a whole different question of creating constructors, so let's set that aside.) gives me this data structure:

 defaultdict(<class 'dict'>, {'dev': {'sha': '5b7', 'url': '/path/to/here'}, 
                             'shared': {'sha': '58a', 'url': '/path/to/there'}})

I'd like to validate this data structure so I create this:

 snapshot_schema = val.Schema({"dictitems":dict,"dev":dict,"shared":dict})

This successfully validates that I have one defaultdict containing two dicts. I'd like to validate that the sha and url tags in both of those dicts are really str (and more validation later maybe.)

I could create an additional schema

 new_schema = Schema({'sha':str, 'url':str})
 new_schema(my_data['dev'])
 new_schema(my_data['shared'])

But is there a more elegant way of doing this?

Upvotes: 0

Views: 1286

Answers (1)

Ray Salemi
Ray Salemi

Reputation: 5913

Turns out one answer is to put the new_schema into the snapshot_schema:

   repo_schema = Schema({"sha":str,"url":str})
   snapshot_schema = Schema({"dictitems":dict,"dev":repo_schema,
                                                  "shared":repo_schema})

Also I guess you could do:

snapshot_schema=Schema({"dictitems":dict,   "dev":{"sha":str,"url":str},
                                         "shared":{"sha":str,"url":str})

Upvotes: 1

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