CODEWITHSUNDEEP
pythonalgorithm
denis jardot
denis jardot

Reputation: 33

Retrieve list of weekdays for any case

Hi everybody I have a small issue of coding:
I have a list of numbers from 0 to 6 that represent days of the week from Sunday to Saturday
So Sunday = 0 and Saturday = 6 So the list is [0,1,2,3,4,5,6]

There is no problem to retrieve the list between two days (or number) if the from < to.
example:
from Monday= 1 to Thursday= 4 there are these numbers included : [1,2,3,4]

Problems come when you have to retrieve the list of days when from > to: example:
from Friday = 5 to Tuesday =2 we need to catch this list : [5, 6, 0, 1, 2]

Do you have idea how can I code an algorithm or a function that will give me a list of days (here numbers) to include if I give a number "from" and a number "to" whatever "from" is inferior or superior to the "to" value.

Thank you very much for your help.

Upvotes: 0

Views: 93

Answers (4)

MMelvin0581
MMelvin0581

Reputation: 503

days_of_week = [0,1,2,3,4,5,6]
day_1 = 5
day_2 = 2

def days_needed(days_of_week, day_1, day_2, rollover=True):
    if rollover:
        day_list = days_of_week[day_1:day_2 - 1:-1]
    else:
        day_list = days_of_week[day_1:day_2 + 1]
    return day_list

day_list = days_needed(days_of_week,day_1,day_2,rollover=True)

print(day_list)

This should do it. Let me know if you need any tweaking.

Upvotes: 0

wohe1
wohe1

Reputation: 775

I would do it this way:

def getweekdays(frm, to):
    days = [0,1,2,3,4,5,6]
    if frm <= to:
        return days[frm:to+1]
    else:
        return days[frm:] + days[:to+1]

(I haven't checked the code, but you get the idea :) )

Upvotes: 4

Ajax1234
Ajax1234

Reputation: 71451

You can use list slicing:

s = [0,1,2,3,4,5,6]
days_of_week = dict(zip(['sun', 'mon', 'tue', 'wed', 'th', 'fri', 'sat'], s))
def get_days(day_range):
   return range(days_of_week[day_range[0]], days_of_week[day_range[-1]]+1) if days_of_week[day_range[0]] <= days_of_week[day_range[-1]] else s[days_of_week[day_range[0]]:]+s[:days_of_week[day_range[-1]]+1]

ranges = [['fri', 'tue'], ['th', 'sat'], ['mon', 'th']]
print(list(map(get_days, ranges))))

Output:

[[5, 6, 0, 1, 2], [4, 5, 6], [1, 2, 3, 4]]

Upvotes: 0

ipop
ipop

Reputation: 34

The easiest aproach for this would be:

day = first_day
while int day != last_day:
    interval_days.add(day)
    if day > 6:
        day = 0

Initialize the day counter at the bottom limit of the day, then keep increasing the counter until the day matches the top limit, if it goes over the biggest day (6) you set it back into the first day of the week(0).

Upvotes: 0

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