Reputation: 979
I'm using HTML slim for the code below.
.page
.paper
button.button.js-copier I copy things
- content_for :js_includes do
javascript:
var startingHtml = $('.page').html();
function initializePlugin() {
$('.js-copier').each(function () {
$(this).on('click', function () {
$('.page').append(startingHtml);
$(document).trigger('page-refreshed');
});
});
}
// Run it right away
initializePlugin();
$(document).on('page-refreshed', initializePlugin);
Is there a way to fix the fact that when I click on the "I copy things" button, it creates multiple copies of the button as it is iterating over all the button from the button that was selected?
Also, is there a better way to write this code. All I'm trying to do is duplicate the button anytime I click on any buttons(first and any new button created buttons)
-Anthony
Upvotes: 0
Views: 230
Reputation: 12161
First change this:
$('.js-copier').each(function () {
$(this).on('click', function () {
...
to this:
$('.page').on('click', '.js-copier', function () {
...
Read this to understand https://learn.jquery.com/events/event-delegation/#event-propagation
Then remove the 'page-refreshed' event because you don't need it:
$(document).trigger('page-refreshed');
...
$(document).on('page-refreshed', initializePlugin);
Demo solution:
var startingHtml = $('.page').html();
function initializePlugin() {
$('.page').on('click', '.js-copier', function () {
$('.page').append(startingHtml);
});
}
// Run it right away
initializePlugin();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="page">
<div class="paper">
<button class="button js-copier"> I copy things</button>
</div>
</div>
Upvotes: 2