CODEWITHSUNDEEP
scala
John
John

Reputation: 1591

Split without Index out of bound exception

Is there any simple way to split safely by avoiding index bound of exception?

For example:

"1-2".split("-")(1) == "2"
"1".split("-")(1) == null

Upvotes: 3

Views: 2500

Answers (3)

bottaio
bottaio

Reputation: 5093

This functionality is already implemented in Array. lift method returns None for an out of bounds index, otherwise it returns Some(value)

val array = Array(3, 5, 1)
array.lift(5) // None
array.lift(0) // Some(3)

Upvotes: 15

vindev
vindev

Reputation: 2280

You can wrap your Operation using scala.util.Try and then do getOrElse over it. If the value at that index exists it will return that value else it will return the value specified in getOrElse. Try following code for your above given scenario.

scala.util.Try("1".split("-")(1)).getOrElse(null)
//output
null

Upvotes: 3

Sergii Lagutin
Sergii Lagutin

Reputation: 10681

Scala Array doesn't provide safety method to get element by index. So you should consider IndexOutOfBoundsException. Possible ways:

use Try and test it if success:

scala.util.Try(array(index))

add own method:

implicit class RichArray[A](array: Array[A]) {
  def opt(index: Int): Option[A] =
    if (array.length < 0 || array.length <= index) None
    else Some(array(index))
}

val array = Array(12, 3, 4)

array.opt(2) // Some(4)
array.opt(3) // None

Upvotes: 3

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