Reputation: 14573
I've got a template class:
template <typename T> struct randimpl {
// default is to not compile, have to pass T to something to get assert
// evaluated during second phase expansion, is_void is an arbitrary choice.
static_assert(
std::is_void<T>::value && false, "random() not implemented for type"
);
};
This is just a proxy for a random()
function that can be overloaded for user-defined types:
// random function, proxies request through randimpl
template <typename T> T random() {
return randimpl<T>::random();
}
Which I'm trying to partially specialize for a type _point1d<T>
:
// generate random instances _point1d<T>
template <typename T>
struct randimpl<_point1d<T>> {
static _point1d<T> random() {
return _point1d<T>(random<T>());
}
};
Which as far as I can tell is the appropriate syntax, but when I compile, I get:
inc/geometry.h: In static member function ‘static _point1d<T> randimpl<_point1d<T> >::random()’:
inc/geometry.h:287:31: error: expected primary-expression before ‘(’ token
return _point1d<T>(random<T>());
^
inc/geometry.h:287:40: error: expected primary-expression before ‘>’ token
return _point1d<T>(random<T>());
^
inc/geometry.h:287:42: error: expected primary-expression before ‘)’ token
return _point1d<T>(random<T>());
Is my syntax off? This seems like it should work, but I don't understand why it's not accepting it.
Upvotes: 3
Views: 90
Reputation: 172924
The problem is that the static
member function's name random
hides the global one, it's trying to invoke itself (i.e. recursive call). But it's not a template and doesn't match how it's called.
You can add ::
(scope resolution) to specify the global random
, e.g.
// generate random instances _point1d<T>
template <typename T>
struct randimpl<_point1d<T>> {
static _point1d<T> random() {
return _point1d<T>(::random<T>());
// ^^
}
};
Upvotes: 3