Reputation: 315
Why isn't this standalone code working:
$link = 'https://google.com';
$unacceptables = ['https:','.doc','.pdf', '.jpg', '.jpeg', '.gif', '.bmp', '.png'];
foreach ($unacceptables as $unacceptable) {
if (strpos($link, $unacceptable) === true) {
echo 'Unacceptable Found<br />';
} else {
echo 'Acceptable!<br />';
}
}
It's printing acceptable every time even though https is contained within the $link
variable.
Upvotes: 30
Views: 53349
Reputation: 488
strpos
function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE.
So I did like this
if (strpos($link, $unacceptable) !== false) {
//Code
}
Upvotes: 1
Reputation: 3559
Strpos always return position like you search "httpsL" in your string('https://google.com';) then it return 0th position and PHP evaluate it as false.
please see this link:(Hope its very usefull for you): http://php.net/manual/en/function.strpos.php
Upvotes: 2
Reputation: 26251
Your failure condition is wrong.
strpos returns false if match is not found, so you need to explicitly check
if (strpos($link, $unacceptable) !== false) {
Upvotes: 8
Reputation: 12900
strpos() does not return true when it finds a match, it returns the position of the first matching string. Watchout, if the match is a the beginning of the string it will return an index of zero which will compare as equal to false unless you use the === operator.
Upvotes: 15
Reputation: 80041
When in doubt, read the docs:
[strpos] Returns the numeric position of the first occurrence of needle in the haystack string.
So you want to try something more like:
// ...
if (strpos($link, $unacceptable) !== false) {
Because otherwise strpos
is returning a number, and you're looking for a boolean true
.
Upvotes: 80