CODEWITHSUNDEEP
javajsonjacksondeserializationobjectmapper
Partha
Partha

Reputation: 310

Map dynamic field names while deserializing a JSON to a Java object

I have an interesting problem that I want to solve. This is while I am parsing a response from one of the platforms that we interact with. The response changes based on the User.

Say for User A, I have the following JSON :

{
 "userId": "AA001",
 "AA001_Name": "Username",
 "AA001_Email": "[email protected]",
 "AA001_Phone": "000-000-0000"
}

For User B, I have :

{ 
  "userId" : "AA002",
  "AA002_Name" : "Username",
  "AA002_Email" : "[email protected]",
  "AA002_Phone" : "000-000-0000"
}

Now, while deserializing, I want to map both of them to the following object, ignoring the field name the json came with :

class User {
  private String userId,
  private String name,
  private String email,
  private String phone
}

It is easy to map the userId, as that's the field in the JSON as well, but what about the custom fields?

Now, I can't use the @JsonProperty as the name of the field is dynamically changing based on the user.

Is there any way this could be accomplished? Please note that I might have several such custom objects like Department, Organization etc, and the platform returns the data in such a manner, meaning the keys have the user-specific information appended.

Any help is appreciated. I am badly stuck at this.

Upvotes: 1

Views: 2656

Answers (2)

fps
fps

Reputation: 34470

I think you can't do any better than using @JsonCreator:

class User {

    private String userId;
    private String name;
    private String email;
    private String phone;

    @JsonCreator
    public User(Map<String, Object> map) {
        this.userId = (String) map.get("userId");
        map.entrySet().stream()
            .filter(e -> e.getKey().endsWith("_Name"))
            .findFirst()
            .ifPresent(e -> this.name = (String) e.getValue());
        // repeat for other fields
    }

    // getters & setters (if needed)
}

You can change the stream by a traditional for each on the map's entry set to optimize performance-wise.

Upvotes: 1

CrizR
CrizR

Reputation: 688

You can't use @JSONProperty as is, but what if you reformatted the keys before deserializing the JSON? I.E 

  String key = "AA001_Name"
  String[] key = key.split("_") 
  key[0] = "AA001"
  key[1] = "Name"
  //Use key[1] as the new field name

Do this for each key, create a new JSON Object with the correct field names, then deserialize it.

Upvotes: 0

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