Reputation: 401
I created a program in Prolog which returns following powers of two starting from one:
twos(N, L) :- twosH(N, 1, L).
twosH(0, _, L) :- L = [], !.
twosH(N, I, [R|L]) :- R is 2*I, N1 is N-1, twosH(N1, R, L).
I would like it to use difference list instead of regular one. I know how to append an element to difference list:
appendD(A-B, B-C, A-C).
but I don't know how to incorporate it into my program.
Upvotes: 1
Views: 45
Reputation: 58254
If you use a DCG, then you are using a difference list:
powers_of_2(0, 1) --> [1].
powers_of_2(N, PT) --> [PT], { PT #= 2 * PT1, N #> 0, N #= N1 + 1 }, powers_of_2(N1, PT1).
powers_of_2(N, PT) :-
phrase(powers_of_2(N, _), PT).
| ?- powers_of_2(4, P).
P = [16,8,4,2,1] ? ;
no
| ?-
A listing of what the DCG looks like as standard predicates (obtained by entering listing.
then I changed the variable names a little):
powers_of_2(0, 1, [1|T], T).
powers_of_2(N, PT, [PT|PTs], T) :-
PT #= 2 * PT1,
N #> 0,
N #= N1 + 1,
powers_of_2(N1, PT1, PTs, T).
If you called it directly, you would give it the empty list as the final tail:
| ?- powers_of_2(4, P, PT, []).
P = 16
PT = [16,8,4,2,1] ? ;
no
If you want the numbers in the reverse order, I'll leave that as an exercise. :)
Upvotes: 2