Search and replace the following in vi

Question

Hi I want to replace the occurrence of [x] with [] in vi editor

I have used the following command

:%s/[x]/[]

and it gives me [[]], how to update my command so that I get desired result.

Answer 1

You can replace:

• It once (the first occurrence on the current line) with: :s/\[x\]/[]/
• It everywhere on the current line with :s/\[x\]/[]/g
• The first occurence on every line with :%s/\[x\]/[]/
• It everywhere :%s/\[x\]/[]/g

(Obviously you must make sure you are in command mode, use the esc-key for this)