CODEWITHSUNDEEP
pythonpython-3.x
Supreeth KV
Supreeth KV

Reputation: 307

AttributeError: 'datetime.timedelta' object has no attribute 'year'

d1 = datetime.strptime(self.current_date, "%Y-%m-%d")
d2 = datetime.strptime(self.dob, "%Y-%m-%d")

current_age = (d1 - d2).year

Running this code give the following error: 

AttributeError: 'datetime.timedelta' object has no attribute 'year'

Upvotes: 11

Views: 37341

Answers (2)

Andrew Richards
Andrew Richards

Reputation: 1668

Calculating the difference between 2 dates returns a timedelta (datetime.timedelta) such as (d1 - d2) in your sample code ("A timedelta object represents a duration, the difference between two dates or times."). Available from this are .days, .seconds and .microseconds (only). A timedelta isn't anchored to particular years so it doesn't provide .years since the number of leap years can only be accurately counted once a start date is known (timedelta doesn't have this information). Using the Python REPL,

>>> import datetime
>>> datetime.date(2021,1,1) - datetime.date(2020,1,1)
datetime.timedelta(days=366)
>>> datetime.date(2022,1,1) - datetime.date(2021,1,1)
datetime.timedelta(days=365)

For an exact answer take the original dates' year values and then use their month and day values to work out whether the subject's birthday has occurred this year or not. Adapting your sample code and omitting reference to the class you're clearly using (you don't provide the code for that so it's confusing to include it),

from datetime import date

d1 = date.today()
d2 = date(2000, 1, 1)  # Example date

current_age = d1.year - d2.year
if (d1.month, d1.day) < (d2.month, d2.day):
    current_age = current_age - 1  # Not had birthday yet
print(current_age)

Alternatively use the dateutil module's relativedelta which is aware of years. For example,

from datetime import date
from dateutil.relativedelta import relativedelta

d1 = date.today()
d2 = date(2000, 1, 1)  # Example date

current_age = relativedelta(d1, d2).years
print(current_age)

Upvotes: 6

John Zwinck
John Zwinck

Reputation: 249123

As per the docs (https://docs.python.org/3/library/datetime.html), a timedelta counts days, not years. So try something like (d1 - d2).days / 365.25.

Upvotes: 29

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