CODEWITHSUNDEEP
gradlegroovy
Mike3355
Mike3355

Reputation: 12061

zip a file and move it gradle

I am trying zip the contents in the module, exclude the builds folder but it is not running. I do println outside the task and that works but nothing will print inside the task.

task fullZip(type: Zip) {
    baseName = 'client' //name of the module
    from 'client' //name of the module
    exclude 'build'
    into '../docker/client'
    doFirst { println 'before zip' }
    doLast { println 'after zip' }

}

This is a multi module project and I have ran gradle clean build and gradle build The other modules work just fine but their task is to copy a jar and I use assemble.dependsOn at the end of those tasks. That will not work in this case.

I just want to zip up the module and move it to a different directory where I will unzip it.

Upvotes: 0

Views: 1179

Answers (1)

Lukas Körfer
Lukas Körfer

Reputation: 14523

Summary from chat discussion:

task fullZip(type: Zip) {
    baseName = 'client'
    from projectDir
    exclude 'build'
    destinationDir = file('../docker/client')
}

build.dependsOn fullZip

The main problem was the relative path in the from parameter, which did work because is is interpreted relative to the project directory.

Also, according to the docs, the into method ...

Specifies the destination directory inside the archive for the files. The destination is evaluated as per Project.file(java.lang.Object). Don't mix it up with AbstractArchiveTask.getDestinationDir() which specifies the output directory for the archive.

Those two methods were mixed up. Finally, the task was added to the build lifecycle via a task dependency registration.

Upvotes: 1

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